| Re: [tcf-dev] Step Into Selection when execution is already at the selection line |
|
Hi Moshe, It looks like a bug. I will investigate. Thanks, Eugene From: tcf-dev-bounces@xxxxxxxxxxx [mailto:tcf-dev-bounces@xxxxxxxxxxx]
On Behalf Of moshe cikk Hi, I am having problems on my system when using "step into selection" when my execution is already at the selection line, where the execution will just run untill the end of the program. For example, given the following lines of code where foo1 and foo2 are some existing methods: printf("Before"); foo1(foo2(),foo3()); If I was currently at the printf line and performed "step into selection" on foo2, all works fine. If I was currently at the foo1 line and performed "step into selection" on foo2, my program runs past everything. I looked into the implementation of TCFStepIntoSelectionHandler, and my understanding is that there are two steps: Step 1- Place breakpoint at selection line, run, remove the breakpoint. Step 2- Place breakpoint on selection function, run, remove the breakpoint. I assume step 1 is needed so that we don't stop at the selection function before control reaches the selecion line, however when execution is already at the selection line, step 1 (at least in my case) passes the selection function, resulting
in step 2 running untill the end of the program execution. Is there a way I can bypass this? Is it possible to skip step 1 when execution is already at the selection location? Thanks, Moshe Cikk This email and any attachments are intended for the sole use of the named recipient(s) and contain(s) confidential information that may be proprietary, privileged or copyrighted under applicable law. If you are not the intended recipient, do not read, copy, or forward this email message or any attachments. Delete this email message and any attachments immediately. |