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Re: [equinox-dev] Re: How can I register a servlet to receive andhandle the path like "/*"?
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You should just use /scap
see http://www.osgi.org/javadoc/r4v42/org/osgi/service/http/HttpService.html#registerServlet(java.lang.String, javax.servlet.Servlet, java.util.Dictionary, org.osgi.service.http.HttpContext)
HTH
-Simon
"fox" ---12/08/2009 09:33:12 PM---Hi Gunnar: Thanks for your help,
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"fox" <fox@xxxxxxxxxxxxx> |
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12/08/2009 09:33 PM |
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Re: [equinox-dev] Re: How can I register a servlet to receive andhandle the path like "/*"? |
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Hi Gunnar:
Thanks for your help,
but then I found another problem: if I want the servlet to handle the request with the path "/scap/*",I try to modify the alias to "/xcap/", it throws "java.lang.IllegalArgumentException: Invalid alias '/xcap/' ",how should I resolve this problem?
Thanks so many.
2009-12-09
fox
发件人: Gunnar Wagenknecht
发送时间: 2009-12-08 20:31:53
收件人: equinox-dev
抄送:
主题: [equinox-dev] Re: How can I register a servlet to receive andhandle the path like "/*"?
Am 08.12.2009 09:08, schrieb fox:
> When I convert a httpservlet to a bundle,I found that the first param of
> Httpservice.registerServlet method does not support the path define
> like "/*",but I want to achieve this functionality ,what should I do?
Just '/' instead of '/*'. The OSGi HttpService applies a prefix matching.
-Gunnar
--
Gunnar Wagenknecht
gunnar@xxxxxxxxxxxxxxx
http://wagenknecht.org/
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