|
I saw following:
0= 0x22fd24
1= 0x1
2= 0x2
3= 0x3
4=
0x5
The 0-th element is really **m_c_p, but the 1-st is
**m_c_p[0]. I think, it's strange, but I must repeat again, may be I have old
version....
Igor S. Zamyatin
----- Original Message -----
Sent: Thursday, December 04, 2003 10:22
PM
Subject: Re: [cdt-debug-dev]
Demonstrating of arrays
What exactly is wrong? I tried this example and
it seems to work fine.
----- Original Message -----
Sent: Thursday, December 04, 2003 5:37
AM
Subject: [cdt-debug-dev] Demonstrating
of arrays
Hi all!
I found some problem in CDT Debugger, but maybe
just my CDT version too old....
I have such example of code:
int m_a[3][3] = {{1, 2, 3}, {5, 6, 7}, {12, 13,
14}};
int* m_a_p =
m_a[0];
int** m_b_p
= &m_a_p;
int ***
m_c_p = &m_b_p;
I try to watch by m_c_p in variables view. I expand it and
see *m_c_p. Then I want to "display as array" *m_c_p for example 5 elements.
ThereI can be seen wrong results... First element displays correctly,
but others...
Igor S. Zamyatin
Interstron Ltd.
www.interstron.ru
|
