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How to add a new UML Property as subset of an UML Class in EML [message #1731705]

Mon, 09 May 2016 12:20

Mohammadreza Sharbaf

Messages: 22
Registered: February 2016

Junior Member

Hi,

I would like to merge two UML Class Diagrams. For this purpose first I compare two models using ECL and it works correctly. After that I merge them together by following EML code:


pre{
	for (p in Target!Package) { 
		delete p ; 
	}
	var Pack  ;
}

rule MergePackage
	merge l : Left!Package with r : Right!Package into t : Target!Package {
	
	t.name = l.name + " and " + r.name;
	Pack := t ; 	
}

rule MergeClass
	merge l : Left!Class with r : Right!Class  into t : Target!Class {
	
	t.name = l.name;
	t.isAbstract = l.isAbstract;
	
	Pack.packagedElement.add(t);
}

rule MergeProperty
	merge l : Left!Property with r : Right!Property into t : Target!Property{
	
	t.name = l.name ; 
}

By using ".packagedElement.add()" I can add new Class to my package, But I don't know how must add new Property to my Class.

This figure shows the result obtained :

and this figure shows the expected result:

I've attached a MinimalExample for you. Can you help me?

Best Regards,
Mohammadreza

Attachment: MinimalExampaleMerge.rar
(Size: 2.18KB, Downloaded 368 times)

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Re: How to add a new UML Property as subset of an UML Class in EML [message #1731934 is a reply to message #1731705]

Wed, 11 May 2016 08:04

Antonio Garcia-Dominguez

Messages: 594
Registered: January 2010
Location: Birmingham, UK

Senior Member

Hi Mohammadreza,

You can use eContainer to access the Class of the left Property, for instance, and then use equivalent() or equivalents() to obtain the target class that was produced by MergeClass. It's easy from there:

rule MergeProperty
	merge l : Left!Property with r : Right!Property into t : Target!Property{
	
	t.name = l.name ;
	l.eContainer.equivalent().ownedAttributes.add(t); 	 
}

Kind regards,
Antonio

[Updated on: Wed, 11 May 2016 08:05]

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