Home » Modeling » Papyrus » Interface realisation
| Interface realisation [message #1522527] |
Mon, 22 December 2014 06:12  |
Eclipse User |
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Hi,
If I create an interface with two operations and a class that realises
that interface using the "InterfaceRealization" edge only one (the
first) operation is shown in the operations compartment (after F4). Is
this by design or is this a bug in Papyrus?
TIA
Joost
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| Re: Interface realisation [message #1547818 is a reply to message #1522527] |
Mon, 05 January 2015 12:15  |
| Eclipse User |
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Hi,
When pressing F4, are you trying to display the operations on the Class, or on the Realized Interface?
If I reproduce your steps:
- Pressing F4 on the Interface gives me all the operations (As expected)
- Pressing F4 on the Class gives me nothing (Probably not as expected, but I don't see the "Only one operation" behavior)
Creating a Generalization between 2 classes shows the expected behavior (i.e. all Operations are displayed in both the Super- and Sub- Class), so I guess there is no specific support for Interface Realization links (Only for Generalizations).
I don't know if the UML Specification says anything about that. For inherited attributes, it's clear that Interface's attributes are not Inherited via an InterfaceRealization link, but I didn't see anything for Operations. In general, Operation inheritance in UML is not really specified.
HTH,
Camille
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| Re: Interface realisation [message #1551296 is a reply to message #1551265] |
Wed, 07 January 2015 09:36 |
| Eclipse User |
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Hi, Joost,
I think this would be as expected. Interface realization does not have
Generalization semantics, so features of an interface are not inherited
by realizing classifiers (only by specializing interfaces). The UML is
quite vague about how a realizing classifier is expected to realize the
features of its interfaces (it's a semantic variation point).
Cheers,
Christian
On 2015-01-07 14:11:04 +0000, Joost Kraaijeveld said:
> On 05/01/15 18:15, Camille Letavernier wrote:
>> Hi,
>>
>>
>> When pressing F4, are you trying to display the operations on the Class,
>> or on the Realized Interface?
>>
>> If I reproduce your steps:
>>
>> - Pressing F4 on the Interface gives me all the operations (As expected)
>> - Pressing F4 on the Class gives me nothing (Probably not as expected,
>> but I don't see the "Only one operation" behavior)
> I would have expected to see the operations, as the link is "Realized
> Interface "
>
>
> Gr
>
> Joost
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| Re: Interface realisation [message #1551432 is a reply to message #1551296] |
Wed, 07 January 2015 11:21 |
| Eclipse User |
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Hash: SHA1
On 07-01-15 15:36, Christian W. Damus wrote:
> Hi, Joost,
>
> I think this would be as expected. Interface realization does not
> have Generalization semantics, so features of an interface are not
> inherited by realizing classifiers (only by specializing
> interfaces). The UML is quite vague about how a realizing
> classifier is expected to realize the features of its interfaces
> (it's a semantic variation point)
In the current specification (2.4.1) is stated "For behavioral
features, the implementing classifier will have an operation or
reception for every operation or reception, respectively, defined by
the interface." (7.3.25, semantics). My expectation was based on this.
The 2.5 beta 2 specification does not have such explicit statement but
that states "Instead, an Interface specification is implemented or
realized by a BehavioredClassifier, which means that the
BehavioredClassifier presents a public facade that conforms to the
Interface specification." (10.4.3 Semantics). And I cannot see another
implementation than that if an interface has an operation the
realizing BehavioredClassifier should have such an operation. But I
may be missing alternative implementations.
Gr
Joost
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| Re: Interface realisation [message #1551453 is a reply to message #1551432] |
Wed, 07 January 2015 11:36 |
| Eclipse User |
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Hi, Joost,
Yes, for behavioral features I agree with your interpretation. I just
don't know that any kind of "inheritance" as such is implied as with
generalizations. I rather think not, that instead the implementing
classifier has to define its own corresponding behavioral features (or
inherit them from general classifiers), but I could be wrong!
(wouldn't be the first time)
Christian
On 2015-01-07 16:21:01 +0000, Joost Kraaijeveld said:
> -----BEGIN PGP SIGNED MESSAGE-----
> Hash: SHA1
>
> On 07-01-15 15:36, Christian W. Damus wrote:
>> Hi, Joost,
>>
>> I think this would be as expected. Interface realization does not
>> have Generalization semantics, so features of an interface are not
>> inherited by realizing classifiers (only by specializing
>> interfaces). The UML is quite vague about how a realizing
>> classifier is expected to realize the features of its interfaces
>> (it's a semantic variation point)
>
> In the current specification (2.4.1) is stated "For behavioral
> features, the implementing classifier will have an operation or
> reception for every operation or reception, respectively, defined by
> the interface." (7.3.25, semantics). My expectation was based on this.
>
> The 2.5 beta 2 specification does not have such explicit statement but
> that states "Instead, an Interface specification is implemented or
> realized by a BehavioredClassifier, which means that the
> BehavioredClassifier presents a public facade that conforms to the
> Interface specification." (10.4.3 Semantics). And I cannot see another
> implementation than that if an interface has an operation the
> realizing BehavioredClassifier should have such an operation. But I
> may be missing alternative implementations.
>
> Gr
>
> Joost
>
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> lkgAn1pCoP4AT9ZStVJ+IOmr3sDgvCw9
> =yNde
> -----END PGP SIGNATURE-----
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| Re: Interface realisation [message #1697004 is a reply to message #1522527] |
Sat, 30 May 2015 13:29 |
| Eclipse User |
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This is seriously problematic. If you have a class that is realized by an interface, all behavioral features should be available for the class as well.
If you create an interface with one operation, and you realize a class based on this interface, the operation should be accessible in sequence diagram, but is not. While on generalization this works just fine.
In Java, this should look like
public class SomeClass implements SomeInterface {
...
}
In the UML Superstructure 2.4.1, page 89, it says
"An interface realization relationship between a classifier and an interface implies that the classifier supports the set of
features owned by the interface, and any of its parent interfaces. For behavioral features, the implementing classifier will
have an operation or reception for every operation or reception, respectively, defined by the interface."
This is pretty clear description of the expected behavior, however this is not supported by Papyrus as I see it right now.
Or I am missing something.
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| Re: Interface realisation [message #1707999 is a reply to message #1697004] |
Fri, 11 September 2015 06:47 |
| Eclipse User |
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When I run the Model Validator on a specialisation of an Interface, I got warnings that an invaild type is specialized. I do not see a way to inherit from an interface in uml.
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