| GMF gmftool gmfgraph gmfmap, changes in gmftool, gmfgraph after gmfmap is created [message #220090] |
Thu, 26 February 2009 15:06  |
Eclipse User |
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Originally posted by: ralph.schreder.knowis.de
Hello,
I want to insert a separator between 2 Nodes in the palette (gmftool). I
have created gmfmap before. I have Eclipse-version 3.4.1 and GMF 2.1.3.
In the gmfmap is noticed the index to the gmftool file (creation node).
After the change (separator inserted) is the index bad for gmfmap.Why
can't I refer to an String alias, so that the relation still exists to
creect item as before?
Do anybody knows about GMF version 2.2, that it can be resolved without
to make changes in gmfmap afterwords.
Exists a possibility for version 2.1.x?
The same is for gmfgraph. Because gmfmap works with indices to gmftool
and gmfgraph, any changes to gmfgraph, gmftool, I must correct gmfmap.
Thank you for an answer,
Ralph
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| Re: GMF gmftool gmfgraph gmfmap, changes in gmftool, gmfgraph after gmfmap is created [message #220155 is a reply to message #220090] |
Fri, 27 February 2009 01:29  |
| Eclipse User |
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Hello Ralph,
After creating a gmfmap you need to edit the gmftool and gmfgraph resouces
from within the gmfmap. Otherwise the dependencies won't be handled
correctly as you have noticed already.
Best regards
Enrico
Ralph Schreder wrote:
> Hello,
> I want to insert a separator between 2 Nodes in the palette (gmftool). I
> have created gmfmap before. I have Eclipse-version 3.4.1 and GMF 2.1.3.
> In the gmfmap is noticed the index to the gmftool file (creation node).
> After the change (separator inserted) is the index bad for gmfmap.Why
> can't I refer to an String alias, so that the relation still exists to
> creect item as before?
> Do anybody knows about GMF version 2.2, that it can be resolved without
> to make changes in gmfmap afterwords.
> Exists a possibility for version 2.1.x?
> The same is for gmfgraph. Because gmfmap works with indices to gmftool
> and gmfgraph, any changes to gmfgraph, gmftool, I must correct gmfmap.
>
> Thank you for an answer,
> Ralph
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