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how to open a file in the actual project [message #1162222]

Wed, 30 October 2013 04:27

Eclipse User

in the XTEND for my generator i want to access files which are under the roof of my current project.
I evaluate resource.URI.trimSegments(2) which will result in "platform:\resource\abf"
but this does not work well with my
new FileReader(resource.URI.trimSegments(2)+"\\!includefiles\\a.sampletext")

How can I get an absolute path to my project directory out of "platform:\resource\abf"?
Or is theresomething which returns the path of the workspace aka "platform:\resource"

Re: how to open a file in the actual project [message #1162241 is a reply to message #1162222]

Wed, 30 October 2013 04:43

Eclipse User

Check out the URIConverter registered to the ResourceSet. You should not rely on FileReader nor on Windows style paths, just URIs and getting an InputStream for them.

Re: how to open a file in the actual project [message #1162273 is a reply to message #1162241]

Wed, 30 October 2013 05:11

Eclipse User

Hi Karsten,

I have not found a hint in the XTEXT or XTEND documentation.
as I am a novice on the XTEND,XTEXT,JAVA,... I have problems to interpret the infos I googled.

Perhaps I have caused some confusion: This "includefile" are not to be included in the generator and evaluated there, its just a term from the customer which denotes some files with simple text to be added to the generated output here and there.

Can you give me a little help how to implement this?

Under my project roof, I have a directory "boilerplatetex" where "a.sampletext" resides.
In my generator, I want to grab the contents of this file, modify it and add it to the output.

Its just some boilerplate text to be included; depending on customers choice, these boilerplatefiles may later reside in a fixed directory on a windows fileserver or under the different projects. I need an option to handle all of these situations.

TIA, Uli

[Updated on: Wed, 30 October 2013 05:31] by Moderator

Re: how to open a file in the actual project [message #1162355 is a reply to message #1162222]

Wed, 30 October 2013 06:16

Eclipse User

May be this helps.

import org.eclipse.xtext.ui.refactoring.impl.ProjectUtil

@Inject ProjectUtil projectUtil

val inputStream = projectUtil.findFileStorage(uri, false).getContents()

Re: how to open a file in the actual project [message #1162363 is a reply to message #1162355]

Wed, 30 October 2013 06:25

Eclipse User

Hi Thomas,

I added your lines to my generator.xtend, but got a lot off error markers

Re: how to open a file in the actual project [message #1162472 is a reply to message #1162222]

Wed, 30 October 2013 07:55

Eclipse User

Maybe I have to explain a little bit more:

I work on my generator.xtend.

Then I launch an eclipse runtime.

There I have a java project
abf
|--src
. |- abc.mydsl

|--textfiles
. |- my.text

And I create another java project XYZ
XYZ
|--src
. |- abc.mydsl

|--textfiles
. |- my.text

The src/abc.mydsl is the one I edit and save.
With the doGenerate, I want to access the textfiles/my.text of the project my DSL file belongs to

[Updated on: Wed, 30 October 2013 07:57] by Moderator

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