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| Re: cannot add XMemberFeatureCall to sealed type XExpression [message #911283 is a reply to message #910940] |
Tue, 11 September 2012 09:42  |
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On 09/10/2012 06:57 PM, Hallvard Trætteberg wrote:
> On 10.09.12 07.01, Lorenzo Bettini wrote:
>>
>> I was trying to redefine in my grammar the rule for XMemberFeatureCall
>> as follows:
>>
>> FieldAccess returns xbase::XMemberFeatureCall:
>> PrimaryExpression
>> (=>({XAssignment.assignable=current} '.'
>> feature=[types::JvmIdentifiableElement|ValidID]
>> ))*
>> ;
>>
>> but I get this error from Xtext validator:
>>
>> "cannot add XMemberFeatureCall to sealed type XExpression"
>
> To redefine the grammar for XMemberFeatureCall, you'll need to use the
> same rule name, and it should return the same as the original, i.e.
> xbase::XExpression.
>
> Hallvard
But in the seven languages examples (the template example,
http://www.eclipse.org/Xtext/7languagesDoc.html#template ), I read
something like
RichStringIf returns xbase::XIfExpression:
{RichStringIf}
"IF" if=XExpression
then=RichString
(else=RichStringElseIf | "ELSE" else=RichString)?
"ENDIF";
which is similar to what I was implementing...
Lorenzo
--
Lorenzo Bettini, PhD in Computer Science, DI, Univ. Torino
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