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How to get access to the current project location? [message #876921]

Fri, 25 May 2012 10:28

Eclipse User

Hi all

I use Xtext and a JvmModelInfer.Xtend to generate java file. My generated java file is "c:/topfolder/my.project/src-gen/manager/Customer.java" and after the generation of this file, i would like to add information into this file:
"c:/topfolder/my.project/src-gen/manager/Order.java"
to achieve this, i must get the project folder name: "c:/topfolder/my.project" from my JvmModelInfer.Xtend code and i don't know how to do that. Please Help me
Thank

Re: How to get access to the current project location? [message #876983 is a reply to message #876921]

Fri, 25 May 2012 12:12

Eclipse User

The project name is part of the resource URI
(platform:/resource/yourProjectName/src ..).

What kind of information do you want to add?

Regards,
Sebastian
--
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Am 25.05.12 16:28, schrieb kisito Mising name:
> Hi all
>
> I use Xtext and a JvmModelInfer.Xtend to generate java file. My
> generated java file is
> "c:/topfolder/my.project/src-gen/manager/Customer.java" and after the
> generation of this file, i would like to add information into this file:
> "c:/topfolder/my.project/src-gen/manager/Order.java"
> to achieve this, i must get the project folder name:
> "c:/topfolder/my.project" from my JvmModelInfer.Xtend code and i don't
> know how to do that. Please Help me
> Thank

Re: How to get access to the current project location? [message #876988 is a reply to message #876983]

Fri, 25 May 2012 12:33

Eclipse User

Thank Sebastian

I think, the ressource uri is relative to platform scheme. But i don't know if it's possible to get a java.io.File object using a platform scheme or using a org.eclipse.emf.common.util.URI object.
I want to add or update class members into an existing java file
Best Regard

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