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In an AST Visitor, how can I know which node's property I am visiting? [message #644465]

Sat, 11 December 2010 13:01

Eclipse User

Hi, I'm programming an AST Visitor.

An EnumDeclaration node contains the following structural properties:

JAVADOC, MODIFIERS, NAME, SUPER_INTERFACE_TYPES, ENUM_CONSTANTS and BODY_DECLARATIONS.

When I visit a child node of EnumDeclaration (a SimpleName node, for instance), is it possible to know which of the lists of nodes I'm visiting? Is it possible to differentiate?

I'd like to process a node differently, depending on whether I found it in ENUM_CONSTANTS or BODY_DECLARATIONS.

Thanks for the help.

[Updated on: Sun, 12 December 2010 05:36] by Moderator

Re: In an AST Visitor, how can I know which node's property I am visiting? [message #644498 is a reply to message #644465]

Sun, 12 December 2010 05:35

Eclipse User

Using the accept method it is possible to do this.

List<Node> as = node.<getPropertyX>();
for( Node a: as)
    a.accept( this);

Re: In an AST Visitor, how can I know which node's property I am visiting? [message #644568 is a reply to message #644465]

Mon, 13 December 2010 05:10

Eclipse User

On 2010-12-11 19:01, Joan Robert wrote:
> When I visit a child node of EnumDeclaration (a SimpleName node, for
> instance), is it possible to know which of the lists of nodes I'm
> visiting? Is it possible to differenciate?

Use "node.getLocationInParent() == EnumDeclaration.NAME_PROPERTY" or
other *_PROPERTY constants.

Markus

Re: In an AST Visitor, how can I know which node's property I am visiting? [message #644571 is a reply to message #644568]

Mon, 13 December 2010 05:25

Eclipse User

That's a good alternative way, Markus.

[Updated on: Wed, 15 December 2010 10:56] by Moderator

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