| Is EMF Compare right for this use-case? [message #621138] |
Wed, 15 July 2009 17:57 |
 No real name
Messages: 61
Registered: July 2009 |
Member |
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Hi,
I am not sure if EMF Compare is right for my task. I want JUnit-test
T2M-transformations. For this reason, the test creates a model from some
text. Then I need to compare it with a reference-model.
I already implemented it like this:
MatchModel match = MatchService.doMatch(referenceModel,
createdModel, Collections.<String, Object> emptyMap());
DiffModel diff = DiffService.doDiff(match, false);
List<DiffElement> differences = diff.getOwnedElements();
if( differences.size() > 0 ){
Assert.assertTrue("the created model is different from the
reference-model", false);
}
Unfortunatly, there are differences, even though the model are equal,
except for ID's. But I want to ignore ID's and I just want to know if the
models are "logically" equal.
My simple (UML2-)test-models are:
model 1
<?xml version="1.0" encoding="UTF-8"?>
<uml:Model xmi:version="2.1"
xmlns:xmi="http://schema.omg.org/spec/XMI/2.1"
xmlns:uml="http://www.eclipse.org/uml2/3.0.0/UML"
xmi:id="_Wb9ysXFoEd6xJohxLdzz5Q">
<packagedElement xmi:type="uml:Package" xmi:id="_Wb9ysnFoEd6xJohxLdzz5Q"
name="foo">
<packagedElement xmi:type="uml:Class" xmi:id="_Wb9ys3FoEd6xJohxLdzz5Q"
name="SimpleClass"/>
</packagedElement>
</uml:Model>
model 2
<?xml version="1.0" encoding="UTF-8"?>
<uml:Model xmi:version="2.1"
xmlns:xmi="http://schema.omg.org/spec/XMI/2.1"
xmlns:uml="http://www.eclipse.org/uml2/3.0.0/UML"
xmi:id="_WcG8oHFoEd6xJohxLdzz5Q">
<packagedElement xmi:type="uml:Package" xmi:id="_WcG8oXFoEd6xJohxLdzz5Q"
name="foo">
<packagedElement xmi:type="uml:Class" xmi:id="_WcG8onFoEd6xJohxLdzz5Q"
name="SimpleClass"/>
</packagedElement>
</uml:Model>
If I compare these models with the GUI, it says:
"2 change(s) in <Model>"
- "<Package> foo has been added"
- "<Package> foo has been removed"
Is there maybe some kind of mode that I can use, or is EMF Compare the
wrong choice for this task?
thank you
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