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Birt word wrap [message #526529]

Mon, 12 April 2010 08:00

Wael Mashal

Messages: 10
Registered: January 2010

Junior Member

Hi all

if i have a long string without spaces to view it ,no wrap word work

for example this text "1234567891012345678910123456789101234567891012345678910"

i need to wrap it without spaces like this

"1234567891012345678910
1234567891012345678910
12345678910"

i write a script but the result returned with spaces

"1234567891012345678910123 4567891012345678910123456 78910"

this is the script :

len = "1234567891012345678910123456789101234567891012345678910".length; //gets
length of unbroken string
lines = Math.ceil(len/25); //counts the amount of times you'll have to use the
substr() function
i=1; //initialize line counter
marker = 0; //initialize placeholder
display = ""; //initialize output
//step through the string breaking it up with 25 character segments and adding
a space between segments
while (i<lines){
display = display + "\r" +
"1234567891012345678910123456789101234567891012345678910".substr(marker, 25);
marker = marker + 25;
i++;
}
//use the len variable and marker variable to determine how much is left and
add it to the output variable
display = display + "\r" +
"1234567891012345678910123456789101234567891012345678910".substr(marker,
len-marker);
//output the broken string
display;

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Re: Birt word wrap [message #526596 is a reply to message #526529]

Mon, 12 April 2010 11:56

Wael Mashal

Messages: 10
Registered: January 2010

Junior Member

thanks all i find the solution

if ("1234567891012345678910123456789101234567891012345678910".length > 25) {
length = "123456789101234567891012345 6789101234567891012345678910".length;
"123456789101234567891012345 6789101234567891012345678910".substr(0, 25) + "\u200B" +
"123456789101234567891012345 6789101234567891012345678910".substring(25, length);
} else {
"1234567891012345678910123456789101234567891012345678910";
}

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