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How to get Project of Element or Model [message #473757]

Thu, 05 July 2007 05:36

Francis Gavino

Messages: 57
Registered: July 2009

Member

Hi,

Is there a way to dynamically get the eclipse project (IProject) given the
UML Element or Model?

Thanks,
Francis

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Re: How to get Project of Element or Model [message #473758 is a reply to message #473757]

Thu, 05 July 2007 11:47

Ed Merks

Messages: 33142
Registered: July 2009

Senior Member

Francis,

Here's how to converter between a URI and an IResource:

URI uri =
URI.createPlatformResourceURI(iResource.getFullPath().toStri ng(), true);
IFile iFile = iWorkspaceRoot.getFile(new
Path(uri.toPlatformString(true)));

You can test uri.isPlatformResource() to be sure if the URI is
equivalent to an IFile. Given any EObject x, x.eResource().getURI()
will give you the URI and from that you can determine the IFile and
hance the IProject.

Francis wrote:
> Hi,
>
> Is there a way to dynamically get the eclipse project (IProject) given
> the UML Element or Model?
>
> Thanks,
> Francis
>

Ed Merks
Professional Support: https://www.macromodeling.com/

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Re: How to get Project of Element or Model [message #473946 is a reply to message #473758]

Wed, 11 July 2007 09:23

Francis Gavino

Messages: 57
Registered: July 2009

Member

Thanks Ed for the response. This approach works for me, although I'm using
EMF 2.2 and URI.toPlatformString() is unavailable. I just created my own
method that uses the segments of the URI to achieve the same result.
Thanks again.

Francis

Ed Merks wrote:

> Francis,

> Here's how to converter between a URI and an IResource:

> URI uri =
> URI.createPlatformResourceURI(iResource.getFullPath().toStri ng(), true);
> IFile iFile = iWorkspaceRoot.getFile(new
> Path(uri.toPlatformString(true)));

> You can test uri.isPlatformResource() to be sure if the URI is
> equivalent to an IFile. Given any EObject x, x.eResource().getURI()
> will give you the URI and from that you can determine the IFile and
> hance the IProject.

Report message to a moderator