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Home » Eclipse Projects » Sirius » Placing bordered nodes at the same location when copying a model element
Placing bordered nodes at the same location when copying a model element [message #1842739] Wed, 30 June 2021 09:10
Francesco Bedini is currently offline Francesco BediniFriend
Messages: 26
Registered: March 2018
Junior Member
I am implementing some Java services for allowing changing the type of certain elements:

In the java service, I create a new model element, copy the old attributes and delete the original model element.

I finally managed to make Sirius place it in the same location and with the same size as the previous element, but I can't place the pins on the Container edge at the same position on the new container.
How should I do it?

Calling the service in an Operation "changeContext" like:

And here is the Service code so far:
public void transformToComponent(Component c, ArrayList<EObject> containingViews) {
		final Component newComponent = myFactory.eINSTANCE.createComponent();
                // ... copy attributes ...

		// Give to the new component the same size/position as the old one.
		if (containingViews != null && containingViews.size() > 0) {
			DNodeContainer existingNode = (DNodeContainer) containingViews.get(0);
			IGraphicalEditPart editPart = getEditPart(existingNode);
			if (editPart instanceof ShapeEditPart) {
				ShapeEditPart part = (ShapeEditPart) editPart;
						.addData(new RootLayoutData(existingNode.eContainer(), part.getLocation(), part.getSize()));
			//TODO: Place bordered nodes at the same position:
			existingNode.getOwnedBorderedNodes().stream().forEach(bn -> {
				IGraphicalEditPart editPart2 = getEditPart(bn);
				if (editPart2 instanceof ShapeEditPart) {
					ShapeEditPart part = (ShapeEditPart) editPart2;
							.addData(new RootLayoutData(bn.eContainer(), part.getLocation(), part.getSize()));

		// Delete the old component

Thanks in advance for any hint :)
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[Updated on: Wed, 30 June 2021 09:11]

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