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How to access class attribute from outside of class [message #1837724]

Thu, 04 February 2021 13:34

Eclipse User

Hi,

I am trying to set a conditional style for my edge based upon a boolean attribute from its source node. Intuitively I assumed that the precondition would be aql: self.sourceNode.eGet(condition) but it gives the error that condition is not a variable. So then using the interpreter I selected my source node and did self.condition which gives me the same error. When I do self.name it works fine, and so does feature:condition when I set the conditional style for the node itself. How come feature:condition works but self.condition does not? And how do I access the boolean condition from my edge in order to set the conditional style for my edge?
index.php/fa/39938/0/

I am essentially trying to get the arrow leaving my classes to match the color of the source node as shown in the pic.

Attachment: Screenshot 2021-02-04 135916.png
(Size: 89.39KB, Downloaded 257 times)

[Updated on: Thu, 04 February 2021 14:00] by Moderator

Re: How to access class attribute from outside of class [message #1837749 is a reply to message #1837724]

Fri, 05 February 2021 03:34

Eclipse User

Hi,

You can try by "casting" the type with .oclAsType(package::Type). Make sure to reference your metamodel in the Metamodels property tab on your Diagram Description.

Regards,
Florian

Re: How to access class attribute from outside of class [message #1837756 is a reply to message #1837749]

Fri, 05 February 2021 09:48

Eclipse User

To cast it is the command self.sourceNode.oclAsType(Metamodel::Node).condition?

Because the method oclAtType() seems to return a null for me. In my ecore metamodel I haven't set these variables:
index.php/fa/39942/0/

Because when I do the generated code gives me errors. As I am debugging is it because the generated code does not actually create the type and I need to define the type in Java?

Attachment: Screenshot 2021-02-05 094726.png
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