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| Re: Need your help on a student assignment . [message #1740079 is a reply to message #1739839] |
Tue, 09 August 2016 01:55  |
Eclipse User |
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Hi
You don't provide the question and so the notation is meaningless and
the answer is very moot.
OCL has no =>, -->, or [] operators, so I suggest that you post your
question on a more appropriate forum.
In OCL, you would at least need a metamodel to express the edge
relationship, or to justify use of oclContainer() to navigate to parent.
An OCL expression for one characteristic might be something like
Q::allInstances()->closure(oclContainer())-exists(oclIsKindOf(P))
Regards
Ed Willink
On 09/08/2016 03:59, Guillaume Beaudry wrote:
> Need your help with this assignment. My university teacher gave us this practice exam and the answers.
>
> Still i think he made a mistake in the photo i uploaded in the post.
>
>
> The exercise was to write an expression that described each graph.
>
> I think he use the "lead to" symbol in a wrong way.
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> I believe the answer should be:
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> A[] ( (P and Q) => A<>W ) or (P and Q) --> W
>
> and
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> E<> (P => A<> Q)
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> Is he correct or is my own answer ok ?
>
> Thanks
>
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