Eclipse Community Forums: Eclipse Platform

Home » Eclipse Projects » Eclipse Platform » MultipageEditorPart

Tue, 08 January 2008 21:23

Eclipse User

Originally posted by: sandip.sahoo1980.gmail.com

Hi,

I am implementing MultipageEditorPart. Whether it is possible to know
whether the Editor is open/active or not inside the EditorPart? As far as I
know there is no such API provided such as isActive().

Would anybody please provide me any solution for the above?

Regards,
Sandip

Re: MultipageEditorPart [message #323805 is a reply to message #323798]

Wed, 09 January 2008 02:59

Eclipse User

Originally posted by: merks.ca.ibm.com

This is a multi-part message in MIME format.
--------------030300030607020903070706
Content-Type: text/plain; charset=ISO-8859-1; format=flowed
Content-Transfer-Encoding: 7bit

Sandip,

Using the type of technique below within an editor, you can monitor
activation and deactivation of your editor. Maybe you can test
"getSite().getPage().getActiveEditor() == this" but I'm not sure if
that's true when the editor doesn't have focus...

protected IPartListener partListener =
new IPartListener()
{
public void partActivated(IWorkbenchPart p)
{
if (p instanceof ContentOutline)
{
if (((ContentOutline)p).getCurrentPage() == contentOutlinePage)
{
getActionBarContributor().setActiveEditor(LibraryEditor.this );

setCurrentViewer(contentOutlineViewer);
}
}
else if (p instanceof PropertySheet)
{
if (((PropertySheet)p).getCurrentPage() == propertySheetPage)
{
getActionBarContributor().setActiveEditor(LibraryEditor.this );
handleActivate();
}
}
else if (p == LibraryEditor.this)
{
handleActivate();
}
}
public void partBroughtToTop(IWorkbenchPart p)
{
// Ignore.
}
public void partClosed(IWorkbenchPart p)
{
// Ignore.
}
public void partDeactivated(IWorkbenchPart p)
{
// Ignore.
}
public void partOpened(IWorkbenchPart p)
{
// Ignore.
}
};

public void init(IEditorSite site, IEditorInput editorInput)
{
setSite(site);
setInputWithNotify(editorInput);
setPartName(editorInput.getName());
site.setSelectionProvider(this);
site.getPage().addPartListener(*partListener*);
}

public void dispose()
{
updateProblemIndication = false;

getSite().getPage().removePartListener(*partListener*);

adapterFactory.dispose();

if (getActionBarContributor().getActiveEditor() == this)
{
getActionBarContributor().setActiveEditor(null);
}

if (propertySheetPage != null)
{
propertySheetPage.dispose();
}

if (contentOutlinePage != null)
{
contentOutlinePage.dispose();
}

super.dispose();
}

Sandip Sahoo wrote:
> Hi,
>
> I am implementing MultipageEditorPart. Whether it is possible to know
> whether the Editor is open/active or not inside the EditorPart? As far as I
> know there is no such API provided such as isActive().
>
> Would anybody please provide me any solution for the above?
>
> Regards,
> Sandip
>
>
>

--------------030300030607020903070706
Content-Type: text/html; charset=ISO-8859-1
Content-Transfer-Encoding: 7bit

<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<meta content="text/html;charset=ISO-8859-1" http-equiv="Content-Type">
</head>
<body bgcolor="#ffffff" text="#000000">
Sandip, 
 
Using the type of technique below within an editor, you can monitor
activation and deactivation of your editor.  Maybe you can test
"getSite().getPage().getActiveEditor() == this" but I'm not sure if
that's true when the editor doesn't have focus... 
 
  protected IPartListener partListener = 
    new IPartListener() 
    { 
      public void partActivated(IWorkbenchPart p) 
      { 
         if (p instanceof ContentOutline) 
         { 
           if (((ContentOutline)p).getCurrentPage() ==
contentOutlinePage) 
           { 
            
getActionBarContributor().setActiveEditor(LibraryEditor.this ); 
 
             setCurrentViewer(contentOutlineViewer); 
           } 
         } 
         else if (p instanceof PropertySheet) 
         { 
           if (((PropertySheet)p).getCurrentPage() == propertySheetPage) 
           { 
            
getActionBarContributor().setActiveEditor(LibraryEditor.this ); 
             handleActivate(); 
           } 
         } 
         else if (p == LibraryEditor.this) 
         { 
           handleActivate(); 
         } 
      } 
      public void partBroughtToTop(IWorkbenchPart p) 
      { 
         // Ignore. 
      } 
      public void partClosed(IWorkbenchPart p) 
      { 
         // Ignore. 
      } 
      public void partDeactivated(IWorkbenchPart p) 
      { 
         // Ignore. 
      } 
      public void partOpened(IWorkbenchPart p) 
      { 
         // Ignore. 
      } 
    }; 
 
 
  public void init(IEditorSite site, IEditorInput editorInput) 
  { 
    setSite(site); 
    setInputWithNotify(editorInput); 
    setPartName(editorInput.getName()); 
    site.setSelectionProvider(this); 
    site.getPage().addPartListener(partListener); 
  } 
 
 
  public void dispose() 
  { 
    updateProblemIndication = false; 
 
    getSite().getPage().removePartListener(partListener); 
 
    adapterFactory.dispose(); 
 
    if (getActionBarContributor().getActiveEditor() == this) 
    { 
      getActionBarContributor().setActiveEditor(null); 
    } 
 
    if (propertySheetPage != null) 
    { 
      propertySheetPage.dispose(); 
    } 
 
    if (contentOutlinePage != null) 
    { 
      contentOutlinePage.dispose(); 
    } 
 
    super.dispose(); 
  } 
 
 
Sandip Sahoo wrote:
<blockquote cite="mid:fm1b7m$4r6$1@build.eclipse.org" type="cite">
<pre wrap="">Hi,

I am implementing MultipageEditorPart. Whether it is possible to know
whether the Editor is open/active or not inside the EditorPart? As far as I
know there is no such API provided such as isActive().

Would anybody please provide me any solution for the above?

Regards,
Sandip

</pre>
</blockquote>
 
</body>
</html>

--------------030300030607020903070706--

Re: MultipageEditorPart [message #323809 is a reply to message #323798]

Wed, 09 January 2008 04:17

Eclipse User

PlatformUI.getWorkbench().getActiveWorkbenchWindow().getActi vePage().getActiveEditor();
returns the active editor.
PlatformUI.getWorkbench().getActiveWorkbenchWindow().getActi vePage().getEditorReferences();
returns an array of references to open editors.

Snjeza

Sandip Sahoo wrote:
> Hi,
>
> I am implementing MultipageEditorPart. Whether it is possible to know
> whether the Editor is open/active or not inside the EditorPart? As far as I
> know there is no such API provided such as isActive().
>
> Would anybody please provide me any solution for the above?
>
> Regards,
> Sandip
>
>

Re: MultipageEditorPart [message #323839 is a reply to message #323805]

Wed, 09 January 2008 13:25

Eclipse User

Originally posted by: sandip.sahoo1980.gmail.com

This is a multi-part message in MIME format.

------=_NextPart_000_0015_01C852A9.FE748960
Content-Type: text/plain;
charset="iso-8859-1"
Content-Transfer-Encoding: quoted-printable

Hi Ed,

Thanks.

Itz working.
Even I have tried with below. seems working also.
@Override

public void setFocus() {

super.setFocus();

}

Regards,

Sandip

"Ed Merks" <merks@ca.ibm.com> wrote in message =
news:fm1uos$9v2$1@build.eclipse.org...
Sandip,

Using the type of technique below within an editor, you can monitor =
activation and deactivation of your editor. Maybe you can test =
"getSite().getPage().getActiveEditor() =3D=3D this" but I'm not sure if =
that's true when the editor doesn't have focus...

protected IPartListener partListener =3D
new IPartListener()
{
public void partActivated(IWorkbenchPart p)
{
if (p instanceof ContentOutline)
{
if (((ContentOutline)p).getCurrentPage() =3D=3D =
contentOutlinePage)
{
=
getActionBarContributor().setActiveEditor(LibraryEditor.this );

setCurrentViewer(contentOutlineViewer);
}
}
else if (p instanceof PropertySheet)
{
if (((PropertySheet)p).getCurrentPage() =3D=3D =
propertySheetPage)
{
=
getActionBarContributor().setActiveEditor(LibraryEditor.this );
handleActivate();
}
}
else if (p =3D=3D LibraryEditor.this)
{
handleActivate();
}
}
public void partBroughtToTop(IWorkbenchPart p)
{
// Ignore.
}
public void partClosed(IWorkbenchPart p)
{
// Ignore.
}
public void partDeactivated(IWorkbenchPart p)
{
// Ignore.
}
public void partOpened(IWorkbenchPart p)
{
// Ignore.
}
};

public void init(IEditorSite site, IEditorInput editorInput)
{
setSite(site);
setInputWithNotify(editorInput);
setPartName(editorInput.getName());
site.setSelectionProvider(this);
site.getPage().addPartListener(partListener);
}

public void dispose()
{
updateProblemIndication =3D false;

getSite().getPage().removePartListener(partListener);

adapterFactory.dispose();

if (getActionBarContributor().getActiveEditor() =3D=3D this)
{
getActionBarContributor().setActiveEditor(null);
}

if (propertySheetPage !=3D null)
{
propertySheetPage.dispose();
}

if (contentOutlinePage !=3D null)
{
contentOutlinePage.dispose();
}

super.dispose();
}

Sandip Sahoo wrote:=20
Hi,

I am implementing MultipageEditorPart. Whether it is possible to know=20
whether the Editor is open/active or not inside the EditorPart? As far =
as I=20
know there is no such API provided such as isActive().

Would anybody please provide me any solution for the above?

Regards,
Sandip=20

=20

------=_NextPart_000_0015_01C852A9.FE748960
Content-Type: text/html;
charset="iso-8859-1"
Content-Transfer-Encoding: quoted-printable

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<HTML><HEAD>
<META http-equiv=3DContent-Type =
content=3Dtext/html;charset=3DISO-8859-1>
<META content=3D"MSHTML 6.00.2900.3157" name=3DGENERATOR>
<STYLE></STYLE>
</HEAD>
<BODY text=3D#000000 bgColor=3D#ffffff>
<DIV>Hi Ed,</DIV>
<DIV> </DIV>
<DIV>Thanks.</DIV>
<DIV> </DIV>
<DIV>Itz working.</DIV>
<DIV>Even I have tried with below. seems =
working=20
also.</DIV>
<DIV>
@Override
public<FONT=20
size=3D2> void=20
setFocus() {
super<FONT=20
size=3D2>.setFocus();
}
Regards,
Sandip</DIV>
<BLOCKQUOTE=20
style=3D"PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px; =
BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">
<DIV>"Ed Merks" <<A =
href=3D"mailto:merks@ca.ibm.com">merks@ca.ibm.com</A>>=20
wrote in message <A=20
=
href=3D"news:fm1uos$9v2$1@build.eclipse.org">news:fm1uos$9v2$1@build.ecli=
pse.org</A>...</DIV>Sandip, Using=20
the type of technique below within an editor, you can monitor =
activation and=20
deactivation of your editor.  Maybe you can test=20
"getSite().getPage().getActiveEditor() =3D=3D this" but I'm not sure =
if that's=20
true when the editor doesn't have focus...   =
protected=20
IPartListener partListener =3D     new=20
IPartListener()     =
{      =20
public void partActivated(IWorkbenchPart =
p)      =20
{          if (p instanceof=20
ContentOutline)         =20
{            if=20
(((ContentOutline)p).getCurrentPage() =3D=3D=20
=
contentOutlinePage)          &n=
bsp;=20
=
{             =20
=
getActionBarContributor().setActiveEditor(LibraryEditor.this ); &nb=
sp;     &nb sp;    =20
=
setCurrentViewer(contentOutlineViewer);      =
    =20
}         =20
}          else if (p instanceof=20
PropertySheet)         =20
{            if=20
(((PropertySheet)p).getCurrentPage() =3D=3D=20
=
propertySheetPage)          &nb=
sp;=20
=
{             =20
=
getActionBarContributor().setActiveEditor(LibraryEditor.this );  &=
nbsp;     & nbsp;   =20
=
handleActivate();          &nbs=
p;=20
}         =20
}          else if (p =3D=3D=20
LibraryEditor.this)         =20
{           =20
handleActivate();         =20
}       =
}       public=20
void partBroughtToTop(IWorkbenchPart =
p)      =20
{          //=20
Ignore.       =
}      =20
public void partClosed(IWorkbenchPart =
p)      =20
{          //=20
Ignore.       =
}      =20
public void partDeactivated(IWorkbenchPart=20
p)      =20
{          //=20
Ignore.       =
}      =20
public void partOpened(IWorkbenchPart =
p)      =20
{          //=20
Ignore.       }    =20
};   public void init(IEditorSite site, =

IEditorInput editorInput)   {    =20
setSite(site);    =20
setInputWithNotify(editorInput);    =20
setPartName(editorInput.getName());    =20
site.setSelectionProvider(this);    =20
site.getPage().addPartListener(partListener);  =20
}   public void dispose()  =20
{     updateProblemIndication =3D=20
false;    =20
=
getSite().getPage().removePartListener(partListener); &nbsp=
;  =20
adapterFactory.dispose();     if=20
(getActionBarContributor().getActiveEditor() =3D=3D =
this)    =20
{      =20
getActionBarContributor().setActiveEditor(null);     =

}     if (propertySheetPage !=3D=20
null)     {      =20
propertySheetPage.dispose();     =
}    =20
if (contentOutlinePage !=3D null)    =20
{      =20
contentOutlinePage.dispose();    =20
}     super.dispose();  =20
} Sandip Sahoo wrote:=20
<BLOCKQUOTE cite=3Dmid:fm1b7m$4r6$1@build.eclipse.org =
type=3D"cite"><PRE wrap=3D"">Hi,

I am implementing MultipageEditorPart. Whether it is possible to know=20
whether the Editor is open/active or not inside the EditorPart? As far =
as I=20
know there is no such API provided such as isActive().

Would anybody please provide me any solution for the above?

Regards,
Sandip=20

</PRE></BLOCKQUOTE> </BLOCKQUOTE></BODY></HTML>

------=_NextPart_000_0015_01C852A9.FE748960--

Previous Topic:	Programmatically add a file to a project
Next Topic:	viewShortcut and Key Bindings

Goto Forum:

-=] Back to Top [=-

Current Time: Sat Jul 12 00:06:02 EDT 2025

.:: Contact :: Home ::.

Breadcrumbs

Sign up to our Newsletter