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Mon, 22 July 2013 10:56

Eclipse User

There is no Object created for the terminal rule and neither the parser rules
AbstractElement:
KeyValuePair
;
KeyValuePair:
KVP
;

terminal fragment END:
'\r\n'|'\n'
;
terminal KVP:
('a'..'z'|'A'..'Z')(.)* END
;

so what is the problem here?

Thanks advance

[Updated on: Mon, 22 July 2013 11:26] by Moderator

Re: about grammar again [message #1072364 is a reply to message #1072340]

Mon, 22 July 2013 11:47

Eclipse User

it seems that if there is no java class generated for the parser rule without feature nor the terminal rule

Re: about grammar again [message #1072382 is a reply to message #1072340]

Mon, 22 July 2013 12:40

Eclipse User

Why don't u use the -> operator as it is done in default terminals .
you should have a look at the errors of the workflow. I am sure there
are ones.

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