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How to get the name of the .model file and the folder it resides in? [message #1862300]

Thu, 23 November 2023 08:28

Ehsan Ahmad

Messages: 37
Registered: April 2018

Member

Hi,
I am trying to generate code from using EGL and EGX. I generated class and file name must be same as the file name of the model and it must be placed in a generated folder with the name same as the folder of the model file.

For example, the model file name is "betaFile.model" and it is the folder "alphaFolder". The generator must create a folder "alphaFolder" and then place "betaFile.java" in it.

How to access the model file name "betaFile" and its container "alphaFolder" so that i can set the target in the EGX file as follows:

target: "src/" + package + "/" + c.name + ".java"
to get
src/alphaFolder/betFile.java

thanks

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Re: How to get the name of the .model file and the folder it resides in? [message #1862303 is a reply to message #1862300]

Thu, 23 November 2023 10:38

Dimitris Kolovos

Messages: 2165
Registered: July 2009
Location: York, UK

Senior Member

Hi Ehsan,

If you're using EMF and your model is named M in the run configuration,

M.resource.uri

should return the URI from which the model was loaded.

Thanks,
Dimitris

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Re: How to get the name of the .model file and the folder it resides in? [message #1862307 is a reply to message #1862303]

Thu, 23 November 2023 18:05

Ehsan Ahmad

Messages: 37
Registered: April 2018

Member

Hi Dimitris,
Yes, I am using EMF and it worked.
So, I must hard code the model name (M) in my EOL program.
Is there any other way of getting URI so that the same EOL program can work with other models as well?
Thank you.

[Updated on: Thu, 23 November 2023 18:06]

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Re: How to get the name of the .model file and the folder it resides in? [message #1862309 is a reply to message #1862307]

Thu, 23 November 2023 20:18

Dimitris Kolovos

Messages: 2165
Registered: July 2009
Location: York, UK

Senior Member

You can get the URI of the model containing any (EMF-based) model element using

element.eResource().uri

Thanks,
Dimitris

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Re: How to get the name of the .model file and the folder it resides in? [message #1862312 is a reply to message #1862309]

Thu, 23 November 2023 22:57

Ehsan Ahmad

Messages: 37
Registered: April 2018

Member

Dear Dimitris,

Perfect.

The following statements are working for me.

MyModel.all.first.eResource().uri.trimFileExtension().lastSegment.println(); 
MyModel.all.first.eResource().uri.segment(State.all.first.eResource().uri.segmentCount-2).println();

MyModel is the top most element in the model.

Thank you

[Updated on: Thu, 23 November 2023 23:04]

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