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Fri, 07 July 2006 03:21

Eclipse User

Hi

I am successfull in chating in intranet. I am not able to get how can we
create different groups by using same server. For creating groups we have
do create group in server.xml file and we can connect to the same group
which is mentioned. But if we have to create one more group.
how can we do that?
Do we have to start server for the other one?

Please suggest

Thanks in advance
Digvijay Singh

Re: ECF forming groups [message #606318 is a reply to message #606316]

Fri, 07 July 2006 11:07

Eclipse User

Hi Digvijay,

The default server.xml looks like this (after removing comments):

<server>
<connector protocol="ecftcp" hostname="localhost" port="3282"
timeout="30000">
<group name="server"/>
</connector>
</server>

This group is accessed via URL:

ecftcp://localhost:3282/server

You can add groups to this config file...e.g. to add a group called 'singh':

<server>
<connector protocol="ecftcp" hostname="localhost" port="3282"
timeout="30000">
<group name="server"/>
<group name="singh"/>
</connector>
</server>

And now both the above URL and the following URL should work for
connecting ecf clients:

ecftcp://localhost:3282/singh

Note one requirement is that the groups within a given connector all
have distinct names.

As for your posting about not being able to reach Internet...I can't
immediately tell what the problem is. Could there be a firewall
preventing your access to the Internet? There is a publicly available
group at ecftcp://ecf.eclipse.org:3282/server...you could try to reach
that just to make sure.

Please let us know via list if this does/doesn't help.

Scott

Digvijay S Rana wrote:
> Hi
> I am successfull in chating in intranet. I am not able to get how can we
> create different groups by using same server. For creating groups we
> have do create group in server.xml file and we can connect to the same
> group which is mentioned. But if we have to create one more group. how
> can we do that? Do we have to start server for the other one?
>
> Please suggest
>
> Thanks in advance
> Digvijay Singh
>

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