Skip to main content



      Home
Home » Newcomers » Newcomers » Where to find the identity SAX ContentHandler ?
Where to find the identity SAX ContentHandler ? [message #245775] Thu, 17 January 2008 03:57 Go to next message
Eclipse UserFriend
Originally posted by: none.domain.invalid

Hi,
where can i find the identity SAX ContentHandler ? I mean a contentHandler which write a XML output file which is exactly the same as the XML input file parsed ?

TIA
Re: Where to find the identity SAX ContentHandler ? [message #245790 is a reply to message #245775] Thu, 17 January 2008 05:16 Go to previous messageGo to next message
Eclipse UserFriend
Originally posted by: none.domain.invalid

sorry, i posted to the wrong place..

Name a écrit :
> Hi,
> where can i find the identity SAX ContentHandler ? I mean a
> contentHandler which write a XML output file which is exactly the same
> as the XML input file parsed ?
>
> TIA
Re: Where to find the identity SAX ContentHandler ? [message #245794 is a reply to message #245775] Thu, 17 January 2008 05:19 Go to previous message
Eclipse UserFriend
Originally posted by: merks.ca.ibm.com

This is a multi-part message in MIME format.
--------------080600060401010503030109
Content-Type: text/plain; charset=ISO-8859-1; format=flowed
Content-Transfer-Encoding: 7bit

This article shows some basic things like how to parse an XML document
into DOM and write it back out again:
< http://www.theserverside.com/tt/articles/article.tss?l=Bindi ngXMLJava>

http://www.theserverside.com/tt/articles/article.tss?l=Bindi ngXMLJava

Generally it won't be exactly the same because things like attribute
order is not generally preserved by DOM...


Name wrote:
> Hi,
> where can i find the identity SAX ContentHandler ? I mean a
> contentHandler which write a XML output file which is exactly the same
> as the XML input file parsed ?
>
> TIA


--------------080600060401010503030109
Content-Type: text/html; charset=ISO-8859-1
Content-Transfer-Encoding: 7bit

<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<meta content="text/html;charset=ISO-8859-1" http-equiv="Content-Type">
</head>
<body bgcolor="#ffffff" text="#000000">
This article shows some basic things like how to parse an XML document
into DOM and write it back out again:<a
href=" http://www.theserverside.com/tt/articles/article.tss?l=Bindi ngXMLJava"><br>
</a>
<blockquote><a
href=" http://www.theserverside.com/tt/articles/article.tss?l=Bindi ngXMLJava"> http://www.theserverside.com/tt/articles/article.tss?l=Bindi ngXMLJava</a><br>
</blockquote>
Generally it won't be exactly the same because things like attribute
order is not generally preserved by DOM...<br>
<br>
<br>
Name wrote:
<blockquote cite="mid:fmn575$s7d$1@build.eclipse.org" type="cite">Hi,
<br>
where can i find the identity SAX ContentHandler ? I mean a
contentHandler which write a XML output file which is exactly the same
as the XML input file parsed ?
<br>
<br>
TIA
<br>
</blockquote>
<br>
</body>
</html>

--------------080600060401010503030109--
Previous Topic:Great resource for learning Eclipse and Java
Next Topic:How to change the default workspace settings
Goto Forum:
  


Current Time: Mon Jun 02 18:20:03 EDT 2025

Powered by FUDForum. Page generated in 0.27524 seconds
.:: Contact :: Home ::.

Powered by: FUDforum 3.0.2.
Copyright ©2001-2010 FUDforum Bulletin Board Software

Back to the top