| [Help] How to build DLL using g++ in CDT ? [message #181384] |
Fri, 22 December 2006 21:42 |
Eclipse User |
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Originally posted by: syan.tbdnetworks.com
Hi,
I tried creating a DLL and a tester program in CDT but not very successful.
MyDll project:
// MyDll.cpp : Defines the entry point for the DLL application.
//
#include <iostream>
#include <string>
#include "stdafx.h"
using namespace std;
BOOL APIENTRY DllMain( HANDLE hModule,
DWORD ul_reason_for_call,
LPVOID lpReserved
)
{
cout << "DllMain called" << endl;
return TRUE;
}
int _stdcall sum(int x , int y)
{
cout << "SUM called" << endl;
return x+y;
}
MyDll.def:
LIBRARY MyDll
EXPORTS
sum @1
MyDll.dll is built in debug as:
**** Build of configuration Debug for project MyDll ****
make -k all
Building file: ../MyDll.cpp
Invoking: GCC C++ Compiler
g++ -O0 -g -Wall -c -fmessage-length=0 -MMD -MP -MF"MyDll.d"
-MT"MyDll.d" -o"MyDll.o" "../MyDll.cpp"
Finished building: ../MyDll.cpp
Building target: MyDll.dll
Invoking: GCC C++ Linker
g++ -shared -o"MyDll.dll" ./MyDll.o
Finished building target: MyDll.dll
Build complete for project MyDll
My tester has the following code:
// Get a handle to the DLL module.
hinstLib = LoadLibrary("MyDll");
// If the handle is valid, try to get the function address.
if (hinstLib != NULL)
{
cout << "Got the handle!" << endl;
ProcAdd = (MYPROC) GetProcAddress(hinstLib, "sum");
// If the function address is valid, call the function.
if (NULL != ProcAdd)
{
cout << "Got the function!" << endl;
fRunTimeLinkSuccess = TRUE;
k = (ProcAdd) (i, j);
}
// Free the DLL module.
fFreeResult = FreeLibrary(hinstLib);
}
When I run the program, I can get the handle to the DLL, but cannot get
the function pointer to the DLL.
BTW, I copied the files (.cpp, .def) from VC++ to CDT.
Thanks for your help.
Steve
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