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[Acceleo] tokenize method returning a Bag instead of Sequence [message #1233043]

Sat, 18 January 2014 12:39

michel souza

Messages: 18
Registered: December 2013

Junior Member

Hi guys... according to Acceleo documentation the string method is supposed to return a Sequence(string) but in my case is returning a Bag... no idea why?

Have someone ever experienced that?
It's really important to me have a Sequence(String) instead of a Bag(String). And I don't wanna convert because it messes with the order.

Thank you.

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Re: [Acceleo] tokenize method returning a Bag instead of Sequence [message #1233923 is a reply to message #1233043]

Mon, 20 January 2014 21:14

Stephane Begaudeau

Messages: 458
Registered: April 2010
Location: Nantes (France)

Senior Member

Hi,

Tokenize returns a List<String> which in Acceleo is "translated" as a Sequence(String). What does this ['first.second.third.fourth.fifth'.tokenize('.')/] return for you? If it does not return a sequence with the same order (first, second, third, fourth, fifth), which version of Acceleo are you using, which version of Eclipse and which version of OCL?

Regards,

Stephane Begaudeau, Obeo

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Google+: +stephane.begaudeau
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Re: [Acceleo] tokenize method returning a Bag instead of Sequence [message #1234868 is a reply to message #1233043]

Thu, 23 January 2014 02:14

michel souza

Messages: 18
Registered: December 2013

Junior Member

Hi Stephane,

I figured out the probleam. In fact, my string came from a search that I did with a 'select'.. this select was returning me a collection that wasn't a Sequence.. so I couldn't apply 'first()' operation. I was directly applying resultofsearch.name.tokenize('.')... instead of resultofsearch->asSequence->first().name.tokenize('.') to apply the operation to one single string.

I'm using the lastest versions, I guess.

Many thanks for your help. Merci vraiment pour votre aide!

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