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(Xpand) How to access ecore.ecore via Xpand code [message #947995]

Wed, 17 October 2012 16:50

Adnan AL-SOSWA

Messages: 41
Registered: May 2010

Member

Hi all ,
I have a question about Xpand language . Is it possible that Xpand access the elements of a ecore metamaodel for example ecore.ecore , which does not have model.XMI ? ,attache ecore metamodel ecore.ecore

Thanks in advance

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Re: (Xpand) How to access ecore.ecore via Xpand code [message #948019 is a reply to message #947995]

Wed, 17 October 2012 17:21

Christian Dietrich

Messages: 14665
Registered: July 2009

Senior Member

Hi,
i dont get your point. the ecore.ecore is the model.xmi

~Christian

Twitter : @chrdietrich
Blog : https://www.dietrich-it.de

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Re: (Xpand) How to access ecore.ecore via Xpand code [message #948065 is a reply to message #948019]

Wed, 17 October 2012 18:23

Adnan AL-SOSWA

Messages: 41
Registered: May 2010

Member

Hi Christian,
the model.xmi is the instance of the metammodel ,by creating dynamic instance , my question is how I got all elements of metamodel via Xpand without creating model.xmi , as I want the generated code to access the metamodel elements and not the model.xmi ?

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Re: (Xpand) How to access ecore.ecore via Xpand code [message #948069 is a reply to message #948065]

Wed, 17 October 2012 18:24

Christian Dietrich

Messages: 14665
Registered: July 2009

Senior Member

Can you give an example?

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Twitter : @chrdietrich
Blog : https://www.dietrich-it.de

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Re: (Xpand) How to access ecore.ecore via Xpand code [message #948170 is a reply to message #948069]

Wed, 17 October 2012 20:36

Adnan AL-SOSWA

Messages: 41
Registered: May 2010

Member

Hi ,
For example in my template I want to write something like
for all elements in Ecore
Node_def(element,'attri','attri')
How I can traverse all elements with their attributes .
For the Example of xpand proposed in Eclipse when I create xpand project and choose Generate a sample EMF based on xpand project , I have the metamodel.ecore and when I want to create model.xmi , I choose Eclass "Model" and create dynamic instance from it and continue build my model.xmi accoeding to the structure of metamodel .
but in metamodel ecore.ecore I can not create Model.xmi from it .as I do not know
Which Eclass in ecore.ecore should I choose to create dynamic instance . How I can access ecore.ecore programatically via Xpand
sorry for my bad english and bad explanation Embarrassed

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Re: (Xpand) How to access ecore.ecore via Xpand code [message #948181 is a reply to message #948170]

Wed, 17 October 2012 20:49

Christian Dietrich

Messages: 14665
Registered: July 2009

Senior Member

Hi,

still the question do you want to generate from ecore.ecore as model our from your.ecore an model?
in both cases read the .ecore file and write a template
that operates on EPackages EClasses ......

e.g. for the example project

«DEFINE main FOR ecore::EPackage»
«FILE name+".txt"»
EPackage «name»
EClasses «eClassifiers.typeSelect(ecore::EClass).name.toString(",")»
«ENDFILE»
«ENDDEFINE»

<?xml version="1.0"?>
<workflow>
	<property name="model" value="my.generator.project/src/metamodel/metamodel.ecore" />
	<property name="src-gen" value="src-gen" />
	
	<!-- set up EMF for standalone execution -->
	<bean class="org.eclipse.emf.mwe.utils.StandaloneSetup" >
		<platformUri value=".."/>
	</bean>
	
	<!-- instantiate metamodel -->
	<bean id="mm_emf" class="org.eclipse.xtend.typesystem.emf.EmfRegistryMetaModel"/>

	<!-- load model and store it in slot 'model' -->
	<component class="org.eclipse.emf.mwe.utils.Reader">
		<uri value="platform:/resource/${model}" />
		<modelSlot value="model" />
	</component>


	<!--  generate code -->
	<component class="org.eclipse.xpand2.Generator">
		<metaModel idRef="mm_emf"/>
		<expand
			value="template::Template::main FOR model" />
		<outlet path="${src-gen}" >
			<postprocessor class="org.eclipse.xpand2.output.JavaBeautifier" />
		</outlet>
	</component>
</workflow>

~Christian

Twitter : @chrdietrich
Blog : https://www.dietrich-it.de

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