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extend xbase with a binary literal [message #707387]

Mon, 01 August 2011 15:30

Missing name Missing name

Messages: 4
Registered: August 2010

Junior Member

Hello,

I would like to add binary literals to my DSL that extends xbase. More specifically I would like to be able to type "0b1" (binary 1) "0b10" (binary 2) etc. This syntax is inspired from Python.

For this I followed Jan Koehnlein's very helpful blog post (extending xbase).

and added these rules to my grammar:

XLiteral returns XExpression:
XClosure |
XBooleanLiteral |
...
DecimalLiteral |
BinaryLiteral;

BinaryLiteral:
'0b'binary=ZerosOrOnes;

ZerosOrOnes : ('0'|'1')('0'|'1')*;

When I try this "0b1" and "0b0" are recognized

but I get the error message below for "0b100" :

no viable alternative at input '100'

Any info would be greatly appreciated.
Arye.

[Updated on: Tue, 02 August 2011 10:59]

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Re: extend xbase with a binary literal [message #707425 is a reply to message #707387]

Mon, 01 August 2011 16:35

Christian Dietrich

Messages: 14665
Registered: July 2009

Senior Member

Hi,

the problem is that 100 is recognized as int and not as a 1 and 0 and 0
since the lexer is greedy.

the easiest would be to add the ob into the (now terminal) rule
and registerening a valueconverter to cut it off.

terminal ZerosOrOnes : '0' 'b' ('0'|'1')('0'|'1')*;

~Christian

Twitter : @chrdietrich
Blog : https://www.dietrich-it.de

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