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How to get all the derived classes [message #422692]

Sat, 13 September 2008 10:27

Aline

Messages: 32
Registered: July 2009

Member

Hi,

I was wondering if there is an ecore tool (or sthg else) to get all the
types that can be added in a feature. Typically, I have a class Person,
and two derived classes Male and Female and I want to get both classes
when the input of the feature is an instance of Person.

Can anyone help me ?

Thx in advance,

Aline

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Re: How to get all the derived classes [message #422693 is a reply to message #422692]

Sat, 13 September 2008 10:47

Ed Merks

Messages: 33137
Registered: July 2009

Senior Member

This is a multi-part message in MIME format.
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Content-Type: text/plain; charset=ISO-8859-15; format=flowed
Content-Transfer-Encoding: 7bit

Aline,

This seems related to
< http://ed-merks.blogspot.com/2008/01/creating-children-you-d idnt-know.html>

http://ed-merks.blogspot.com/2008/01/creating-children-you-d idnt-know.html

Generally you can't know all possible derived classes. You need some
way of bounding the search first. Once you have the set of all possible
classes under consideration, you can determine which of them have the
class of interest among its getEAllSuperTypes.

Aline wrote:
> Hi,
>
> I was wondering if there is an ecore tool (or sthg else) to get all
> the types that can be added in a feature. Typically, I have a class
> Person, and two derived classes Male and Female and I want to get
> both classes when the input of the feature is an instance of Person.
>
> Can anyone help me ?
>
> Thx in advance,
>
> Aline
>

--------------090309040406040401030509
Content-Type: text/html; charset=ISO-8859-15
Content-Transfer-Encoding: 8bit

<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<meta content="text/html;charset=ISO-8859-15"
http-equiv="Content-Type">
<title></title>
</head>
<body bgcolor="#ffffff" text="#000000">
Aline,<br>
<br>
This seems related to <a
href=" http://ed-merks.blogspot.com/2008/01/creating-children-you-d idnt-know.html"><br>
</a>
<blockquote><a
href=" http://ed-merks.blogspot.com/2008/01/creating-children-you-d idnt-know.html"> http://ed-merks.blogspot.com/2008/01/creating-children-you-d idnt-know.html</a><br>
</blockquote>
Generally you can't know all possible derived classes.

Ed Merks
Professional Support: https://www.macromodeling.com/

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Re: How to get all the derived classes [message #422710 is a reply to message #422693]

Sun, 14 September 2008 16:58

Aline

Messages: 32
Registered: July 2009

Member

Hi,

Thanks for your answer.
I finally found what I needed and it was very simple -_-'
I just needed to do :
ProjetFactory.eINSTANCE.getEPackage().getEClassifiers();
and then work with the list.

Is there a difference between getEPackage() and getProjetPackage() ? The
results seem to be the same...

Thanks in advance,

Aline

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Re: How to get all the derived classes [message #422713 is a reply to message #422710]

Sun, 14 September 2008 17:43

Ed Merks

Messages: 33137
Registered: July 2009

Senior Member

Aline,

The generated XyzFactory and XyzPackage have specialized getters,
getXyzPackage and getXyzFactory that are effectively the same as
getEPackage and getEFactory, but with a more specialized type. With
Java 5.0's support for covariant return types, we'd likely have just
reused the method name and specified the more specific type that way.
But this was done before Java 5.0 was on the horizon.

In your case, you probably want to use
ProjectPackage.eINSTANCE.getEClassifiers() directly.

Aline wrote:
> Hi,
>
> Thanks for your answer.
> I finally found what I needed and it was very simple -_-'
> I just needed to do :
> ProjetFactory.eINSTANCE.getEPackage().getEClassifiers();
> and then work with the list.
> Is there a difference between getEPackage() and getProjetPackage() ?
> The results seem to be the same...
>
> Thanks in advance,
>
> Aline
>

Ed Merks
Professional Support: https://www.macromodeling.com/

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