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Retreiving the original content of an extended type [message #37043]

Tue, 03 February 2004 08:22

Eclipse User

Originally posted by: niemaz.xrce.xerox.com

Hi,
Is it possible to get the original content model of an extended type?
I thought so and I tried using getTypes methods but it does not seem to
work.
Is there another way to do it?
Next is a simple example I'm working on.

Thanx,

--mike

<xs:complexType name="Address">
<xs:sequence>
<xs:element name="name" type="xs:string"/>
<xs:element name="street" type="xs:string"/>
<xs:element name="city" type="xs:string"/>
</xs:sequence>
</xs:complexType>
<xs:complexType name="UKAddress">
<xs:complexContent>
<xs:extension base="Address">
<xs:sequence>
<xs:element name="country" type="xs:string"/>
</xs:sequence>
<xs:attribute name="exportCode" type="xs:positiveInteger" fixed="1"/>
</xs:extension>
</xs:complexContent>
</xs:complexType>

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Re: Retreiving the original content of an extended type [message #37077 is a reply to message #37043]

Tue, 03 February 2004 22:16

David Steinberg

Messages: 489
Registered: July 2009

Senior Member

mike wrote:
> Is it possible to get the original content model of an extended type?
> I thought so and I tried using getTypes methods but it does not seem to
> work.

Hi Mike,

XSDComplexTypeDefinition.getBaseTypeDefinition() returns the type that was
extended. Cast that result to XSDComplexTypeDefinition, and call
getContentType() on it to get its content model.

Cheers,
Dave

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