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Access to Esuper classes of an Eclass in Acceleo [message #1787161]

Sun, 20 May 2018 17:35

mamad .

Messages: 15
Registered: March 2018

Junior Member

hi guys,
I have a relationship in my MetaModel like below :
eclass3 -> eclass2 -> eclass1
it means eclass1 is Esupertype of eclass2 and eclass2 is Esupertype of eclass3 .
Can i access to eclass1 from eclass3 in Acceleo Templates?
some thing like [eclass1->parent->parent /] !!

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Re: Access to Esuper classes of an Eclass in Acceleo [message #1787167 is a reply to message #1787161]

Mon, 21 May 2018 07:34

Ed Willink

Messages: 7655
Registered: July 2009

Senior Member

Hi

eClass3.eSuperTypes.eSuperTypes should work, but remember that this is a shortform for eClass3.eSuperTypes->collect(c:EClass | c.eSuperTypes) so that the first eSuperTypes return a Collection whose member's eSuperTypes are gathhered into a flat, rather than nested Collection.

Often eClass3->closure(eSuperTypes) which is short for eClass3.oclAsSet()->closure(c:EClass | c.eSuperTypes) is more useful.

If you really want an exactly two level eSuperType ancestor and you are sure that exactly one exists: eClass3.eSuperTypes->any(true).eSuperTypes->any(true)

Regards

Ed Willink

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Re: Access to Esuper classes of an Eclass in Acceleo [message #1787184 is a reply to message #1787167]

Mon, 21 May 2018 14:07

mamad .

Messages: 15
Registered: March 2018

Junior Member

Hi ,dear Ed Willink
Thanks for your reply.
I try [let eclass2 _temp : eclass2 = eclass3.eClass().eSuperTypes->any(true) ]
It runs without error but it gives me a warning and also don't works properly.
Warning is : Possible incompatible type between 'eclass2 ' and 'EClass'.

[Updated on: Mon, 21 May 2018 14:08]

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