| How can a viewer get the model of a GEF editor? [message #136486] |
Sun, 06 June 2004 10:26  |
Eclipse User |
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Originally posted by: beenmerg.yahoo.com
I have a working GEF editor. The editor extends
GraphicalEditorWithPalette. The editor works like every other editor with
a model:
protected void initializeGraphicalViewer() {
getGraphicalViewer().setContents(new MyModel());
}
Now I'm trying to make a viewer that displays a list of the names of all
the elements in the model. The viewer extends ViewPart and is a
TableViewer.
But how can the viewer get the model of the editor? At this moment the
viewer creates a dummy model on the fly. How can I get a reference to the
model that the GEF editor uses so I can use the real model in the viewer?
Many, many thanks in advance for the answer
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| Re: How can a viewer get the model of a GEF editor? [message #136498 is a reply to message #136486] |
Sun, 06 June 2004 12:54  |
| Eclipse User |
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Originally posted by: rlemaigr.ulb.ac.be
Hello Jan,
What you are trying to do looks like an outline view of your editor...Wh=
y =
don't you provide an outline page ? The outline page can be bluid in the=
=
EditorPart class of your editor and so you can pass a reference to the =
model or to the GraphicalViewer in the constructor of the outline page. =
If =
you don't know how to build an outline page I can explain this to you he=
re =
or you can find examples on the net too.
But maybe the outline page is already used for another purpose ?
You could use some kind of multiple page outline page, like in the logic=
=
example...
If you really don't want to build an outline page, then I don't really =
know.
My ideas:
- Maybe you could get a reference to the EditorPart with its identificat=
or =
(but what if there are many Editors of this kind opened on different fil=
es =
?),
- Maybe you could listen to the workbench, I think the workbench can =
notify you when the active Editor changes. So when you recieve such an =
event, you check the id of the current editor and if it is your editor, =
=
you can get its model and display what you want.
I never did this so I am not sure.
I hope this has helped you,
r=E9gis
On Sun, 6 Jun 2004 10:26:59 +0000 (UTC), Jan Groot <beenmerg@yahoo.com> =
=
wrote:
> I have a working GEF editor. The editor extends
> GraphicalEditorWithPalette. The editor works like every other editor w=
ith
> a model:
>
> protected void initializeGraphicalViewer() {
> getGraphicalViewer().setContents(new MyModel());
> }
>
> Now I'm trying to make a viewer that displays a list of the names of a=
ll
> the elements in the model. The viewer extends ViewPart and is a
> TableViewer.
>
> But how can the viewer get the model of the editor? At this moment the=
> viewer creates a dummy model on the fly. How can I get a reference to =
the
> model that the GEF editor uses so I can use the real model in the view=
er?
>
> Many, many thanks in advance for the answer
>
-- =
Using Opera's revolutionary e-mail client: http://www.opera.com/m2/
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| Re: How can a viewer get the model of a GEF editor? [message #136509 is a reply to message #136498] |
Sun, 06 June 2004 13:44 |
| Eclipse User |
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|
Originally posted by: rlemaigr.ulb.ac.be
I know the ISelectionService service tracks the current selection and yo=
u =
can listen to it by writting:
getSite().getWorkbenchWindow().getSelectionService().addSele ctionListene=
r(this);
in the init method of an EditorPart (for a view part it should be the =
same)...
So it must also be some service to track the active editor and this =
service should be accessible from a ViewPart...that's what I am currentl=
y =
searching for...
r=E9gis
On Sun, 06 Jun 2004 14:54:49 +0200, <rlemaigr@ulb.ac.be> wrote:
> Hello Jan,
>
> What you are trying to do looks like an outline view of your =
> editor...Why don't you provide an outline page ? The outline page can =
be =
> bluid in the EditorPart class of your editor and so you can pass a =
> reference to the model or to the GraphicalViewer in the constructor of=
=
> the outline page. If you don't know how to build an outline page I can=
=
> explain this to you here or you can find examples on the net too.
>
> But maybe the outline page is already used for another purpose ?
> You could use some kind of multiple page outline page, like in the log=
ic =
> example...
>
> If you really don't want to build an outline page, then I don't really=
=
> know.
>
> My ideas:
> - Maybe you could get a reference to the EditorPart with its =
> identificator (but what if there are many Editors of this kind opened =
on =
> different files ?),
> - Maybe you could listen to the workbench, I think the workbench can =
> notify you when the active Editor changes. So when you recieve such an=
=
> event, you check the id of the current editor and if it is your editor=
, =
> you can get its model and display what you want.
>
> I never did this so I am not sure.
>
> I hope this has helped you,
>
> r=E9gis
>
>
>
> On Sun, 6 Jun 2004 10:26:59 +0000 (UTC), Jan Groot <beenmerg@yahoo.com=
> =
> wrote:
>
>> I have a working GEF editor. The editor extends
>> GraphicalEditorWithPalette. The editor works like every other editor =
=
>> with
>> a model:
>>
>> protected void initializeGraphicalViewer() {
>> getGraphicalViewer().setContents(new MyModel());
>> }
>>
>> Now I'm trying to make a viewer that displays a list of the names of =
all
>> the elements in the model. The viewer extends ViewPart and is a
>> TableViewer.
>>
>> But how can the viewer get the model of the editor? At this moment th=
e
>> viewer creates a dummy model on the fly. How can I get a reference to=
=
>> the
>> model that the GEF editor uses so I can use the real model in the =
>> viewer?
>>
>> Many, many thanks in advance for the answer
>>
>
>
>
-- =
Using Opera's revolutionary e-mail client: http://www.opera.com/m2/
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| Re: How can a viewer get the model of a GEF editor? [message #136522 is a reply to message #136509] |
Sun, 06 June 2004 13:59 |
| Eclipse User |
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|
Originally posted by: rlemaigr.ulb.ac.be
Bingo ! (you say that in english too ? :D )
I think I have found it:
The service I was searching for is IPartService and you can get it from =
a =
ViewPart like that:
getSite().getWorkbenchWindow().getPartService()
and you can add an IPartListener by calling addPartListener(IPartListene=
r).
So you could add this line in the init method of your view:
getSite().getWorkbenchWindow().getPartService().addPartListe ner(this);
and then implement the IPartListener interface.
There is a method called partActivated(IWorkbenchPart) in this interface=
.. =
This should look like this:
public void partActivated(IWorkbenchPart activePart)
{
if(activePart instanceof YourEditorClass)
setInput(((YourEditorClass)activePart).getContents());
else
setInput(null);
}
and then the dispose method:
getSite().getWorkbenchWindow().getPartService().removePartLi stener(this)=
;
please let me know if it works or if you find a better way...I am =
interested too...
r=E9gis
On Sun, 06 Jun 2004 15:44:00 +0200, <rlemaigr@ulb.ac.be> wrote:
> I know the ISelectionService service tracks the current selection and =
=
> you can listen to it by writting:
>
> getSite().getWorkbenchWindow().getSelectionService().addSele ctionListe=
ner(this);
>
> in the init method of an EditorPart (for a view part it should be the =
=
> same)...
>
> So it must also be some service to track the active editor and this =
> service should be accessible from a ViewPart...that's what I am =
> currently searching for...
>
> r=E9gis
>
> On Sun, 06 Jun 2004 14:54:49 +0200, <rlemaigr@ulb.ac.be> wrote:
>
>> Hello Jan,
>>
>> What you are trying to do looks like an outline view of your =
>> editor...Why don't you provide an outline page ? The outline page can=
=
>> be bluid in the EditorPart class of your editor and so you can pass a=
=
>> reference to the model or to the GraphicalViewer in the constructor o=
f =
>> the outline page. If you don't know how to build an outline page I ca=
n =
>> explain this to you here or you can find examples on the net too.
>>
>> But maybe the outline page is already used for another purpose ?
>> You could use some kind of multiple page outline page, like in the =
>> logic example...
>>
>> If you really don't want to build an outline page, then I don't reall=
y =
>> know.
>>
>> My ideas:
>> - Maybe you could get a reference to the EditorPart with its =
>> identificator (but what if there are many Editors of this kind opened=
=
>> on different files ?),
>> - Maybe you could listen to the workbench, I think the workbench can =
=
>> notify you when the active Editor changes. So when you recieve such a=
n =
>> event, you check the id of the current editor and if it is your edito=
r, =
>> you can get its model and display what you want.
>>
>> I never did this so I am not sure.
>>
>> I hope this has helped you,
>>
>> r=E9gis
>>
>>
>>
>> On Sun, 6 Jun 2004 10:26:59 +0000 (UTC), Jan Groot <beenmerg@yahoo.co=
m> =
>> wrote:
>>
>>> I have a working GEF editor. The editor extends
>>> GraphicalEditorWithPalette. The editor works like every other editor=
=
>>> with
>>> a model:
>>>
>>> protected void initializeGraphicalViewer() {
>>> getGraphicalViewer().setContents(new MyModel());
>>> }
>>>
>>> Now I'm trying to make a viewer that displays a list of the names of=
=
>>> all
>>> the elements in the model. The viewer extends ViewPart and is a
>>> TableViewer.
>>>
>>> But how can the viewer get the model of the editor? At this moment t=
he
>>> viewer creates a dummy model on the fly. How can I get a reference t=
o =
>>> the
>>> model that the GEF editor uses so I can use the real model in the =
>>> viewer?
>>>
>>> Many, many thanks in advance for the answer
>>>
>>
>>
>>
>
>
>
-- =
Using Opera's revolutionary e-mail client: http://www.opera.com/m2/
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