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Xpand suppress return value output [message #534171]

Tue, 18 May 2010 09:39

Dennis

Messages: 2
Registered: May 2010

Junior Member

Hello everybody,

I'm quite new to this topic, and currently I am trying to create a small sample DSL for my Bachelor Thesis...

I succeeded in creating something like a Homepage-DSL for generating html files, and now I would like to develop another generator which creates .tex files from this Homepage DSL Model.

But I'm stuck with the problem of creating tex tables

The output of the generator should look something like:

\begin{tabular}{|l|l|}
Left upper corner&Right upper corner\\
Left lower corner&Right lower corner\\

This is a table with two columns => So i figured to use this:

«DEFINE column FOR Column»
«EXPAND element FOR elements.first()»
«elements.remove(elements.first())»
&«EXPAND element FOREACH elements»
«ENDDEFINE»

The problem is that elements.remove(elements.first()) will print [ ] to my tex code. How do I suppress this output?

Any idea? Thank you!

[Updated on: Tue, 18 May 2010 09:40]

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Re: Xpand suppress return value output [message #534187 is a reply to message #534171]

Tue, 18 May 2010 10:20

MaximeLecourt

Messages: 108
Registered: February 2010
Location: France

Senior Member

I don't really know how to help you, but you can use
elements.withoutFirst() instead of elements.remove(elements.first())

From my experience, [ ] is the sign of a List.

Can you paste what exact text output you get ?

One day I shall master M2T, but that day has yet to come...

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Re: Xpand suppress return value output [message #534200 is a reply to message #534187]

Tue, 18 May 2010 10:55

Christian Dietrich

Messages: 14665
Registered: July 2009

Senior Member

Hello,

have a look at the xtend function toString("SeptaratorString") on a list so {"1","2"}.toStrring("&") delivers 1 & 2

on the other hand why don't you use the SEPARATOR flag on expand:

<<EXPAND element FOEACH elements SEPARATOR "&">>

~Christian

Twitter : @chrdietrich
Blog : https://www.dietrich-it.de

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