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[EMF Compare] Is it possible to ignore the element order? [message #632564]

Wed, 13 October 2010 13:13

Jan Baart

Messages: 2
Registered: October 2010

Junior Member

Hi,

I'm trying to compare a refactored model to a specified target model
using EMF Compare. This is working fine and as expected but I'd like to
give the user an option to ignore re-ordered elements. Because the user
has to manually create a target model this might be more convenient than
making sure the elements have the same order as in the source model.
However, it seems to me there is no way to make EMF Compare ignore the
order.

Am I just overlooking something or is this not possible? I noticed the
papers mention a change of order as a basic possible difference between
models but in certain cases, semantically, reordering is not a
difference at all.

thanks

Jan

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Re: [EMF Compare] Is it possible to ignore the element order? [message #632643 is a reply to message #632564]

Wed, 13 October 2010 17:06

Ed Willink

Messages: 7655
Registered: July 2009

Senior Member

Hi Jan

This should not be a problem.

If the meta-model collection isOrdered then ordering matters.

If the meta-model collection !isOrdered then EMF Compare should be
blind; raise a bug.

Regards

Ed Willink

On 13/10/2010 14:13, Jan Baart wrote:
> Hi,
>
> I'm trying to compare a refactored model to a specified target model
> using EMF Compare. This is working fine and as expected but I'd like to
> give the user an option to ignore re-ordered elements. Because the user
> has to manually create a target model this might be more convenient than
> making sure the elements have the same order as in the source model.
> However, it seems to me there is no way to make EMF Compare ignore the
> order.
>
> Am I just overlooking something or is this not possible? I noticed the
> papers mention a change of order as a basic possible difference between
> models but in certain cases, semantically, reordering is not a
> difference at all.
>
> thanks
>
> Jan

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Re: [EMF Compare] Is it possible to ignore the element order? [message #633048 is a reply to message #632643]

Fri, 15 October 2010 08:19

Laurent Goubet

Messages: 1902
Registered: July 2009

Senior Member

Hi Jan,

As Ed mentionned, we only consider "order" important if you defined it as such in your metamodel. We do not, however, provide a way for the user to ignore order changes in ordered references.

You'll need to open your meta model, select the reference where order isn't important, open its properties (right click => show properties view) and set "ordered" to "false" for EMF Compare to ignore it.

Laurent Goubet
Obeo

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Re: [EMF Compare] Is it possible to ignore the element order? [message #633084 is a reply to message #632564]

Fri, 15 October 2010 10:05

Patrick Konemann

Messages: 116
Registered: July 2009

Senior Member

Hi Jan,

I had a similar issue and maybe this is or interest to you.

The comparisons I have contain a lot of order changes but I am not interested in them.
I'm calling EMF Compare programmatically, so I can access the computed diffmodel.
Before opening the compare UI for the user, I remove all order changes:

org.eclipse.emf.compare.mpatch.util.MPatchUtil.removeDiffEle mentOfType(snapshot.getDiff(), Collections.singleton(DiffPackage.Literals.REFERENCE_ORDER_C HANGE));

MPatchUtil is available in the CVS repository of EMF Compare, or I can post the method here if you like.

Hope it helps
Patrick

On 13-10-2010 15:13, Jan Baart wrote:
> Hi,
>
> I'm trying to compare a refactored model to a specified target model using EMF Compare. This is working fine and as expected but I'd like to give the user an option to ignore re-ordered elements. Because the user has to manually create a target model this might be more convenient than making sure
> the elements have the same order as in the source model. However, it seems to me there is no way to make EMF Compare ignore the order.
>
> Am I just overlooking something or is this not possible? I noticed the papers mention a change of order as a basic possible difference between models but in certain cases, semantically, reordering is not a difference at all.
>
> thanks
>
> Jan

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